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(x^2)=((12.2)^3)
We move all terms to the left:
(x^2)-(((12.2)^3))=0
We add all the numbers together, and all the variables
x^2-1815.848=0
a = 1; b = 0; c = -1815.848;
Δ = b2-4ac
Δ = 02-4·1·(-1815.848)
Δ = 7263.392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{7263.392}}{2*1}=\frac{0-\sqrt{7263.392}}{2} =-\frac{\sqrt{}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{7263.392}}{2*1}=\frac{0+\sqrt{7263.392}}{2} =\frac{\sqrt{}}{2} $
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